Math, asked by Aaravtiwari, 11 months ago

Answer please
with nice explanation .

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Answered by jyoti7397
0
let ramya's one day work is 1
let ramya takes time x days
surya takes time x-40 days
surya's one day work is 3


work =days*one day work
since both works same work

x*1=3*(x-40)
x=60


time taken by both =work/both one day work

60/4
15 days is the ans




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Answered by Vanshika4721
0

Hii I will help you ✌️

=> As given Surya works 3 times as fast as Ramya. It means surya’s efficiency is 3 times as Ramya.

So, time taken by Surya will be 1/3 of time taken by Ramya.

Let no. of days taken by Surya and Ramya are Sd and Rd.

Sd = 1/3 Rd

3Sd = Rd

Given, Rd - Sd = 40

3Sd - Sd = 40

2Sd = 40

Sd = 20 days

Rd = 60 days

If they work together,

Let the time taken to complete is t.

1/t = 1/ Sd + 1/ Rd

1/t = 1/20 + 1/60

1/t = (3+1)/60

1/t = 1/15

t = 15 days

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