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let ramya's one day work is 1
let ramya takes time x days
surya takes time x-40 days
surya's one day work is 3
work =days*one day work
since both works same work
x*1=3*(x-40)
x=60
time taken by both =work/both one day work
60/4
15 days is the ans
let ramya takes time x days
surya takes time x-40 days
surya's one day work is 3
work =days*one day work
since both works same work
x*1=3*(x-40)
x=60
time taken by both =work/both one day work
60/4
15 days is the ans
jyoti7397:
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=> As given Surya works 3 times as fast as Ramya. It means surya’s efficiency is 3 times as Ramya.
So, time taken by Surya will be 1/3 of time taken by Ramya.
Let no. of days taken by Surya and Ramya are Sd and Rd.
Sd = 1/3 Rd
3Sd = Rd
Given, Rd - Sd = 40
3Sd - Sd = 40
2Sd = 40
Sd = 20 days
Rd = 60 days
If they work together,
Let the time taken to complete is t.
1/t = 1/ Sd + 1/ Rd
1/t = 1/20 + 1/60
1/t = (3+1)/60
1/t = 1/15
t = 15 days
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