Question

answer pls pls pls pls

Answer 1

Answer:

$Mode=> \: 20 \:$

Step-by-step explanation:

$Here, \: the \: maximum \: frequency \\ is \: 28 \: and \: the \: class \\ \: corresponding \: to \: this \\ \: frequency \: (also \: known \: as \\ \: modal \: class) \: is \: 40 - 50. \: \\We \: knew \: to \: estimate \: mode\: (Z) \: \\ \: from \: grouped \: data \: \: \\ that \: is, \: \\ = > L+ ( \frac{f _{1} - f_{0}}{2 \times f _{1} - f _{0} - f _{2} } \: ) \times c \\ where :- \\ \: \: L \: (\: the \: lower \: limit \: of \\ \: modal \: class) = 40$

$c \: (the \: size \: of \: class \: interval) = 10$

$f _{1}(the \: frequency \: of \: modal \\ \: class) = 28$

$f _{0}(the \: frequency \: of \: preceding \\ \: class) = 12$

$f _{2}(the \: frequency \: of \: succeeding \\ \: class) = 20$

$Therefore, \\ Z= L +( \frac{f _{1} - f _{0} }{2 \times f _{1} - f _{0} - f _{2} } ) \times c \: \\ = 40 + ( \frac{28 - 12}{2 \times (28 - 12 - 20} ) \times 10 \\ = 40 + ( \frac{16}{ - 8} ) \times 10 \\ = 40 - 20 \\ = > 20$