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Since , exterior angle of a triangle = sum of its opposite interior angles . So Angle ACD= Angle BAC +
Angle ABC
Angle ACD = 70+40
Thus, Angle ACD =110
Angle ABC
Angle ACD = 70+40
Thus, Angle ACD =110
pappya36:
give me full answer plss
sorry it is right answer
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we have given that,
<BAC= 70
<ABC=40
then we know that
abc+bac+acb=180
40+70+acb=180
110+acb=180
acb=180-110
acb=70
hence proved.
<BAC= 70
<ABC=40
then we know that
abc+bac+acb=180
40+70+acb=180
110+acb=180
acb=180-110
acb=70
hence proved.
it is ❌ ans.
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