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acceleration will be 1 m/s2
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Answered by
5
= 100m
u = 10m/s
v = 20m/s
v² = u² + 2ad
so
a = (v² - u²)/(2d) = (20² - 10²)/(2*100) = 1.5m/s²
u = 10m/s
v = 20m/s
v² = u² + 2ad
so
a = (v² - u²)/(2d) = (20² - 10²)/(2*100) = 1.5m/s²
hii
Answered by
4
Given :- distance is travelled 100+100 m because, two times stoped the car.
initial velocity (u) is 10 m/s and final velocity (v) is 20 m/s.
We have to calculate acceleration.
So by using 3rd Law of Kinematics,
Vsquare - Usquare = 2(acceleration) ×(distance)
So, putting values in formula,
acceleration is equal to 2.5 m/ sec square.
Hope this helps you. Give my answer Brainliest please.
initial velocity (u) is 10 m/s and final velocity (v) is 20 m/s.
We have to calculate acceleration.
So by using 3rd Law of Kinematics,
Vsquare - Usquare = 2(acceleration) ×(distance)
So, putting values in formula,
acceleration is equal to 2.5 m/ sec square.
Hope this helps you. Give my answer Brainliest please.
Oh
All the best.
two times stop the car how
kuchh bhi answer Lane ke liye
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