answer plz.....
a 60 kg block is released from rest 80 m above the ground . when it has fallen 60m its kinetic energy is approximately :
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KE = 0.5mv^2
finding the velocity
v^2=u^2+2as
v^2 = 2(9.8)(80)
v = 39.6 m/s
KE = 0.5(60)(39.6)^2
KE = 47044.8 J
finding the velocity
v^2=u^2+2as
v^2 = 2(9.8)(80)
v = 39.6 m/s
KE = 0.5(60)(39.6)^2
KE = 47044.8 J
AJAYMAHICH:
wrong answer h yr vo
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