Math, asked by stylishboy07, 1 year ago

answer plz it's an urgent i will mark u brainlist

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Answered by Devanti
2
=tan60/sin60+cos60
=
 =  \sqrt{3}   \div  (\sqrt{3}  \div 2 )+ (1 \div 2)  \\  \\   =   \sqrt{3}  \div  (\sqrt{3}  + 1) \div 2 \\  \\  = 2 \sqrt{3}  \div ( \sqrt{3}  + 1) \\  \\  = 2 \sqrt{3}  \div ( \sqrt{3}  + 1) \times ( \sqrt{3}  - 1) \div ( \sqrt{3 }  - 1) \\  \\  = 2 \times 3 - 2 \sqrt{3}  \div 3 -  \sqrt{3}  +  \sqrt{3}  - 1 \\  \\  = 6 - 2 \sqrt{3}  \div 2 \\  \\  = 2(3 -  \sqrt{3} ) \div 2 \\  \\  = 3  -  \sqrt{3}  \:  \: answer

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