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if 25cm^3 of 1mol dm^3 HNO3 is added to 50cm^3 of 0.5 KOH solution ,what would be the PH of resulting solution
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moles of HNO3 = 0.025 × 1 = 0.025
moles of KOH = 0.05 × 05 = 0.025
After neutrolization
No KOH or HNO3 remains solution
became neutral
So pH = 7
moles of KOH = 0.05 × 05 = 0.025
After neutrolization
No KOH or HNO3 remains solution
became neutral
So pH = 7
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