answer plz... it's urgent
light of energy 3.5×10^_19 J fall on the cathode of a photo cell . the current through the cell is just reduced to zero by applying a stopping potential of 0.25V
options
2.9×10^_19J
3.1×10^_19J
3.5×10^_19J
3.9×10^_19J
give me solution ... no spam plzzz
Dhinu:
what we have to find ?
work function?
okay
ye 10 ki power (-19) h ya (19) ??
okay
3.1 x 10^(-19) J .. answer h kya ?
okay ... cool! ....
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Ans. is 3.1 x 10^(-19) J ... solution is in the pic :)
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