Question

answer plz.....
the time period for 100 vibrations of a simple pendulum recorded by a stop watch is 20.7+_0.1 sec ,the uncertanity in the final result is??

Answer 1

0.1 out of 20 is about 0.5 out of 100. So that's about 0.5 percent. The uncertainty in the period for a single swing or in the frequency would also be about 0.5%.

Answer 2

0.1 out of 20 is about 0.5 out of 100. So that's about 0.5 percent. The uncertainty in the period for a single swing or in the frequency would also be about 0.5%