Question

#Answer plzzzzz#

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Answer 1

∠AGE = 50°

CONSIDER AC AS DIAMETER..

IN ΔACG

∠ACG = 90°

SO ∠CAG = 40° {ANGLE SUM PROPERTY IN TRIANGLE}

NOW IN ΔACB

∠ABC = 90° {ANGLE SUBTENDED IN SEMI-CIRCLE}

∠CAB = 40°

THEREFORE, ∠ACB = 50°

{ANGLE SUM PROPERTY IN TRIANGLE} → 180 - (90+40) = 50°

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