answer plzzzzz...........
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10 cm/s is the right answer
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masses of both blocks are same
have to use laws of momentum
m1u1+m2u2=(m1+m2)v
v is the common velocity
m×60-m×40=2mv
20m=2mv
v=10
in +ve x direction...
we take u2 negative because it is towards -ve x axis.
hope it will help u
have to use laws of momentum
m1u1+m2u2=(m1+m2)v
v is the common velocity
m×60-m×40=2mv
20m=2mv
v=10
in +ve x direction...
we take u2 negative because it is towards -ve x axis.
hope it will help u
shashankavsthi:
welcome dear!
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