answer plzzzzzzzzz how many litres of water must be added to 1 litre of an aqueous solution of HCl with a PH of 1 to create an aqueous solution with PH of 2?
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Initial pH = 1, i.e. [H+] = 0.1 mole/litre
New pH = 2, i.e. [H+] = 0.01 mole/litre
In case of dilution: M1V1= M2V2
0.1 ×1 =0.01 × V2
V2= 10 litre.
Volume of water added = 9 litre.
New pH = 2, i.e. [H+] = 0.01 mole/litre
In case of dilution: M1V1= M2V2
0.1 ×1 =0.01 × V2
V2= 10 litre.
Volume of water added = 9 litre.
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Question:
How many litres of water must be added to 1 litre an aqueous solution of HCl with a pH of 1 to create an aqueous solution with pH of 2 ?
Solution:
pH = 1 ⇒ [H+] = 10–1 = 0.1 M
pH = 2 ⇒ [H+] = 10–2 = 0.01 M
for dilution of HCl,
M1V1 = M2V2
0.1 × 1 = 0.01 × V2
V2 = 10 L
Volume of water added = 10 – 1 = 9 litre
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