Question

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Answer 1

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Answer 2

According to law of motion there will be no effect of mass on velocity. So let velocity of both objects be v

Let there kinetic energy be K₁ and K₂ and mass be m₁ and m₂.

Now,

We know that at height h kinetic energy of object of mass m = mgh

So,

Total energy at height of 20m,

Energy of first object = m₁gh + K.E.

Energy of first object = 20gh

Energy of second object = m₂gh + K.E.

Energy of second object = 20m₂g

Now,

after travalling 10m.

Total Energy of first object = m₁g(20-10) + K¹(let)

Total Energy of first object = 10m₁g + K¹

Total Energy of second object = 10m₂g + K²

Now,

We know that total energy is always conserved.

So,

For first object ,

10m₁g + K¹ = 20m₁g

K¹ = 10m₁g.....................(i)

For second object,

20m₂g = 10m₂g + K²

K² = 10m₂g............................(II)

Dividing equation one and two,

K¹/K² = m₁/m₂

K¹/K² = 2/4

K¹:K² = 1:2