Question

answer que 2 with explaination

Answer 1

Heya

Answer to your question is:-

Let A, B and C represent the positions of Reshma, Salma and Mandip respectively.
AB = 6cm and BC = 6cm.
Radius OA = 5cm
BM ⊥ AC is drawn.
ABC is an isosceles triangle as AB = BC, M is mid-point of AC. BM is perpendicular bisector of AC and thus it passes through the centre of the circle.
Let AM = y and OM = x then BM = (5-x).
Applying Pythagoras theorem in ΔOAM,
OA2 = OM² + AM²
⇒ 5² = x²+ y² --- (i)
Applying Pythagoras theorem in ΔAMB,
AB²= BM²+ AM²
⇒ 6² = (5-x)² + y² --- (ii)
Subtracting (i) from (ii), we get
36 - 25 = (5-x)²- x² 
⇒ 11 = 25 - 10x
⇒ 10x = 14 ⇒ x= 7/5
Substituting the value of x in (i), we get
y2 + 49/25 = 25
⇒ y2 = 25 - 49/25
⇒ y2 = (625 - 49)/25
⇒ y2 = 576/25
⇒ y = 24/5
Thus,
AC = 2×AM = 2×y = 2×(24/5) m = 48/5 m = 9.6 m
Distance between Reshma and Mandip is 9.6 m.

HOPE THIS HELPS YOU:-))

Answer 2

distance between reshma and mandip is 9.6 m