Math, asked by arbaz4, 1 year ago

answer question 1
my requirment

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Answered by Likun45
0
 cosec^{2}  \theta sec ^{2} \theta =cosec ^{2}  \theta sec ^{2}   \theta

= 1/sin ^{2}  \theta +1/cos ^{2}   \theta
sin^{2}  \theta +cos ^{2} \theta/sin ^{2} \theta * cos ^{2} \theta
we know that, 
 sin^{2} \theta +cos ^{2} \theta = 1<br />= 1</span><span>/sin ^{2} \theta * cos ^{2} \theta
=
cosec ^{2} \theta sec ^{2} \theta


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