The inside of a room has a square Base of side 3.6 m.the inside height of the room is 4m .find (i) the space (INTERNAL VOLUME ) OF THE ROOM. (ii) how many boxes each of dimensions 0.9 m ×40 cm × 25 cm can be placed in the room
abhi178:
dear you didn't mention about length
the length is not mentioned in the question
okay
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actually base of room is square
hence base area =(side length)^2
=(3.6m)^2
=12.96 m^2
now volume of room =base area x height
=12.96 x4 m^3=51.84 m^3
no of boxes = volume of room /volume of one box
=51.84/(0.9m)(40/100m)(25/100m)
=51.84/0.09
=576
hence base area =(side length)^2
=(3.6m)^2
=12.96 m^2
now volume of room =base area x height
=12.96 x4 m^3=51.84 m^3
no of boxes = volume of room /volume of one box
=51.84/(0.9m)(40/100m)(25/100m)
=51.84/0.09
=576
I hope this is helpful kiara
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