Question

Answer question 16! Answer it correct only if you know otherwise I will report your answer! ​

Answer 1

Answer:

Hope This Helps You!!

Answer 2

Answer:

Thus proved!

Step-by-step explanation:

The general nth term of an AP is a + (n -1)d.

 From the given conditions,

 m [a + (m-1)d] = n[ a + (n-1)d)]

=> am + m^2d - md = an + n^2d - nd

=> a(m-n) + (m+n)(m-n)d - (m-n)d = 0

=> (m-n) [ a + (m+n-1)d] = 0

=> { a + [(m+n)-1]d}=0------------------------(i)

=> Equation (i) shows that (m+n)th term=o

=> $a_{m+n} =0$