Answer question no.8 with solution
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Mensuration,
We have a floor which has an area of 15×8 m²
Have to cover this area with tiles of length and breadth 50 cm(0.5m) by 25 cm(0.25m).
Now the area covered by one tile
= (0.5×0.25)m²
= 1.25 m²
So the number of tiles required
= (15×8)/1.25
= 96 tiles
Now if a carpet is laid then 1 m space is left between the edges of the carpet and the floor.
So the area wich is uncovered
= (15×8)-{(15-1)×(8-1)} m²
= 120 - 98 m²
= 22 m²
So the fraction of the floor which is uncovered is when carpet is laid is equal to 22 m².
That's it
Hope it helped ( •̀.̫•́✧ )
We have a floor which has an area of 15×8 m²
Have to cover this area with tiles of length and breadth 50 cm(0.5m) by 25 cm(0.25m).
Now the area covered by one tile
= (0.5×0.25)m²
= 1.25 m²
So the number of tiles required
= (15×8)/1.25
= 96 tiles
Now if a carpet is laid then 1 m space is left between the edges of the carpet and the floor.
So the area wich is uncovered
= (15×8)-{(15-1)×(8-1)} m²
= 120 - 98 m²
= 22 m²
So the fraction of the floor which is uncovered is when carpet is laid is equal to 22 m².
That's it
Hope it helped ( •̀.̫•́✧ )
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