Math, asked by Subham2763, 1 year ago

answer question number 10

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Answered by Magnetron
1
\text{Take L.C.M,}\\\frac{\sqrt7-1}{\sqrt7+1}-\frac{\sqrt7+1}{\sqrt7-1}\\=\frac{(\sqrt7-1)^2-(\sqrt7+1)^2}{(\sqrt7+1)(\sqrt7-1)}\\=\frac{(\sqrt7-1+\sqrt7+1)(\sqrt7-1-\sqrt7-1)}{7-1}\\=\frac{(2\sqrt7)(-2)}{6}\\=-\frac{2\sqrt7}{3}\\\Rightarrow a=0,b=-\frac{2}{3}
Answered by Anonymous
0
Glad help you.
it helps you,
thank you ☻
@vaibhav246

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