answer questions no5......
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Ab =BC AND ALSO BD = CD
SO ANGLE ABC=ANGLE ACB AND ANGLE DBC=ANGLE DBC
now adding both we get
AngleABC +DBC=ANGLE ACB+DBC
ANGLEABD=ANGLE ACD
SO ANGLE ABC=ANGLE ACB AND ANGLE DBC=ANGLE DBC
now adding both we get
AngleABC +DBC=ANGLE ACB+DBC
ANGLEABD=ANGLE ACD
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Answered by
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In∆ABC,AB=AC
=Angle ABC=angle ACB..(eq.i)
In ∆BCD,BD=CD
=Angle DBC=angle DCB..(eq.ii)
Adding eq.i and eq.ii we get
Angle ABD=angle ACD
Hence, proved
=Angle ABC=angle ACB..(eq.i)
In ∆BCD,BD=CD
=Angle DBC=angle DCB..(eq.ii)
Adding eq.i and eq.ii we get
Angle ABD=angle ACD
Hence, proved
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