Question

answer questions no5......

Answer 1

Ab =BC AND ALSO BD = CD
SO ANGLE ABC=ANGLE ACB AND ANGLE DBC=ANGLE DBC
now adding both we get
AngleABC +DBC=ANGLE ACB+DBC
ANGLEABD=ANGLE ACD

Answer 2

In∆ABC,AB=AC
=Angle ABC=angle ACB..(eq.i)
In ∆BCD,BD=CD
=Angle DBC=angle DCB..(eq.ii)
Adding eq.i and eq.ii we get
Angle ABD=angle ACD
Hence, proved