answer quick question number 9
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ar( quadrilateral ABCD) can be broken into two triangles = ar(∆ABD) + ar(∆BCD)
= 1/2 × AL × BD + 1/2 × CM × BD
= 1/2 × BD × ( AL + CM )
Hope it may help you !!!!!
= 1/2 × AL × BD + 1/2 × CM × BD
= 1/2 × BD × ( AL + CM )
Hope it may help you !!!!!
SamratShravan45:
thanks bhai
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