answer quickly guys please
Draw the graph of the polynomial f(x)=-4x +4x-1 Also find the vertex of this parabola.
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Answered by
0
Answer:
By using the quadratic formula we derive the discriminant
D = b^2-4ac
D= 4^2 - 4*4*1
D= 16-16
D= 0
Now,
x = -b+√D/2a and -b-√D/2a
x = -4+0/2 and -4-0/2
x = -2 and -2
Answered by
2
Answer:
For vertex we use formula As :
h = −b2a , here a = -4 And b = 4
So ,
h = 12
SO, the axis of symmetry is x = 12 = 0.5
Put that value in our given polynomial and get
y = -4 ( 12 )2 + 4 ( 12 ) - 1
y = -1 + 2 -1
y = 0
So,
The vertex is ( 0.5 , 0 ) ( Ans )
Step 1 - Now form a table , with different values of x and y As :
y = -4x2 + 4x - 1
x y
-2 -25
-1.5 -16
-1 -9
-0.5 -4
0 -1
0.5 0
1 -1
1.5 -4
2 -9
Step - 2 plot these poit on x -y plane and get
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