The atoms of element y form hexagonal close packing and atoms of element x occupies 2/3 portion of number of tetrahedral voids. Whats the formula of compound.
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The number of atoms in hpc lattice ,Y=6
Tetrahedral voids,X=2 × 6
=12
Only 2/3rd of these will occupy so,
12 × 2/3=8
Therefore X=8,Y=6
Formula will be X₈Y₆ ie. X₄Y₃
chikachika:
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