Physics, asked by Saptadip, 1 year ago

Answer quickly with descriptions, urgent!​

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Answered by kalirajan
1

T= 2pi/R .square root of r^3/g

=1/L. Square root of L^3/LT^-2

IF we bring L INSIDE THE SQ.ROOT IT WILL BECOME L^2

T = Square root of L ^3/L^3 T^-2

L^3 CANCEL EACH OTHER

HERE T^-2 go to numerator and it will be T^ 2. sq.root of T^2 =T

so L.H.S= R.H.S

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