Math, asked by AmazingARPIT, 10 months ago

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AmazingARPIT: answer I will thank you

Answers

Answered by tanmaygorain
1

(a2-b2)sinx+2abcosx=(a2+b2)

(a2-b2)sinx+2abcosx. (a2+b2)

----------------------------------.=------------------

(a2-b2) cosx. (a2-b2)cosx

dividing both side by (a2-b2)cosx

2ab. (a2+b2).

=.tanx + ----------. = -------------secx.

(a2-b2). (a2-b2)

(as we know sinx/cosx=tanx and 1/cosx= secx)

(a2+b2)secx. 2ab

tanx= ------------------- - -----------------------

(a2-b2). (a2-b2)

(a2+b2)secx-2ab

tanx=--------------------------------------------------------

(a2-b2)

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