Question

in a triangle pqr bisectors of angle q and angle r meet at m prove that angle qmr= 90 + 1/2 of angle p

Answer 1

Answer:

p+q+r=p+pqm+mqr+prm+mrq=180

p+2.mqr+2.mrq=180

2(mqr+mrq)=180-p

mqr+mrq=90-p/2

180-qmr=90-p/2

180-90+p/2=qmr

90+p/2=qmr