Question

answer ☝️☝️☝️☝️
Subtract
5x²-4y²+6y-3 from 7x²-2xy+8y² - 3x + 5
tell how it is answer ​

Answer 1

I think there's a slight change in yo question to get the r8 answer

5x²+4y²+6y-3 from 7x²-2xy+8y²-3x+5

7x² - 2xy + 8y² - 3x + 5

- (5x² + 6y + 4y² - 3)

= 7x² - 2xy + 8y² - 3x + 5

-5x² - 6y - 4y² + 3

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= (7-5)x² - 2xy + (8-4)y² - 3x - 6y + 5 + 3

=2x² - 2xy + 4y² - 3x - 6y + 8

Answer 2

1)$\huge\red{AnsWeR}$

$(7x² -2xy +8y² -3x + 5) -(5x² - 4y² + 6y -3 )$

$=>7x²-5x²-2xy+8y²+4y² -3x - 6y+ 5+3$

$=>2x²-2xy+12y² - 3x - 6y+ 8$ANSWER

2)$\huge\red{AnsWeR}$

$(2x² -2xy +4y² - 3x - 6y+8)$

no same variable here .

So,$(2x² -2xy +4y² - 3x - 6y+8)$ ANSWER