Question

Answer :-

$x^2 - 3ax + 2a^2$

Given :-
$\alpha = a$
$\beta = 2a$

To find :-
The required quadratic polynomial.

Solution:-

Let the zeroes of required polynomial be $\alpha\: and\ \textless \ br /\ \textgreater \ \: \beta$

The required quadratic polynomial is given by :-
→$x^2 - (\alpha + \beta ) x + \alpha \beta$
→$x^2 -( a +2a) x + a \times 2a$
→$x^2 - 3ax + 2a^2$

The required quadratic polynomial is :-
$\mathbb\red{x^2 - 3ax + 2a^2}$

Thanks to $\textbf{@Durgapal Singh}$

$\text{Ex - Star leader}$​

Answer 1

Answer:

this is not biology

Explanation:

you should ask it in maths srvtions