answer the 10th problem
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Answer : Let AC be 12 and BD be 16.
Diagonals of rhombus bisect each other perpendicularly.
AC /2=12/2 and BD/2=16/2
AO=6 and BO=8
In triangle AOB, angel AOB is 90
AB²=AO²+BO²
= (6)²+(8)²
= 36+64
AB²= 100
Then, AB=10
Each side rhombus are equal
Therefore, each side of rhombus will be of 10cm
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