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here AB is parallel to HF and DE is parallel to FG ,
thus, here angle CFH = 28° = CDA
(CFH and CDA r corresponding angles so it will be equal to each other )
angle CDA + angle BDE + angle FDE
= 180°
28° + 72° + angle FDE = 180°
angle FDE = 180° - 100°
angle FDE = 80° Answer
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