answer the 2 question plz correctly
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(5)
Let the common ratio be x.
Given the length of a cuboid = 4x.
Given breadth of the cuboid = 2x.
Given the height of the cuboid = x.
Given surface area of cuboid = 1372cm^2.
We know that surface area of cuboid = 2(lb + bh + lh)
1372 = 2(4x * 2x + 2x * x + x * 4x)
1372 = 2(8x^2 + 2x^2 + 4x^2)
1372 = 2(14x^2)
1372 = 28x^2
x^2 = 1372/28
x^2 = 49
x = 7cm.
Therefore the length = 4 * 7
= 28cm.
(6)
Given that the bag contains slip from 3 and 32.
The total number of slips n(S) = 30
Multiple of 4 in between 3 and 32 n(A) = 4,8,12,16,20,24,28.
= 7.
Therefore the required probability P(A) = n(A)/n(S)
= 7/30.
Hope this helps!
Let the common ratio be x.
Given the length of a cuboid = 4x.
Given breadth of the cuboid = 2x.
Given the height of the cuboid = x.
Given surface area of cuboid = 1372cm^2.
We know that surface area of cuboid = 2(lb + bh + lh)
1372 = 2(4x * 2x + 2x * x + x * 4x)
1372 = 2(8x^2 + 2x^2 + 4x^2)
1372 = 2(14x^2)
1372 = 28x^2
x^2 = 1372/28
x^2 = 49
x = 7cm.
Therefore the length = 4 * 7
= 28cm.
(6)
Given that the bag contains slip from 3 and 32.
The total number of slips n(S) = 30
Multiple of 4 in between 3 and 32 n(A) = 4,8,12,16,20,24,28.
= 7.
Therefore the required probability P(A) = n(A)/n(S)
= 7/30.
Hope this helps!
siddhartharao77:
:-)
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