Question

Three resistors are connected as shown in the diagram,
Through the resistor 5 ohm , a current of 1 ampere is flowing .
a) what is the current flowing through the other two resistors ?
b) what is the potential difference across AB and across AC ?
c) What is the total resistance ?
answer with full steps and explanation !!

Answer 1

See the diagram for the circuit.

Voltage across 5Ω = 5*1= 5V.

Net resistance across BC (parallel combination) = 10×15/25 = 6Ω

Voltage across BC (parallel combination) = 6×1 = 6V.
Current thru 10Ω = 6/10= 0.6 A
Current thru 15Ω = 6/15 or 1 -0.6,= 0.4A.

Total resistance across AC: 5+6= 11Ω.
Total potential across AC: 5+6= 11V.

Answer 2

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➧ Total resistance
➾ 1 / 10 + 1 / 15 + 5
➾ 11 ohm

I = 1A 　　　,　　 V = IR

V ➾ 1 × 5
　➾ 5V (ACCROSS AB)

V = 1 × 11
　➾11V (ACCROSS AC)

➧ V (ACCROSS BC i.e OTHER 2 RESISTORS)

➾ 11 - 5
➾ 6V (AC - AB = BC)

➧ I = V / R

I1 = 6 / 10
➾ 0.6 ...✔

I2 = 6 / 15
➾ 0.4 A ...✔

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Thanks...✊