N quadrilateral ABCD, AB produced is perpendicular to DC produced. If A= 44 degree and C= 148 degree, Calculate angle D and angle B.?
Answers
Answered by
44
the point where AB produced is perpendicular to DC= X
we have right angle ΔAXD and ΔBXC
∠D= ∠A- ∠C
= 90-44
= 46
The exterior angle of a triangle equals the sum of the interior angles
∠B = ∠AXD+ ∠XCB
= 90+(180-148)
= 122
we have right angle ΔAXD and ΔBXC
∠D= ∠A- ∠C
= 90-44
= 46
The exterior angle of a triangle equals the sum of the interior angles
∠B = ∠AXD+ ∠XCB
= 90+(180-148)
= 122
Answered by
33
Draw Quadrilateral ABCD and let AB meet DC which was produced at E
Angle A = 44 Degrees
Angle C = 148 Degrees
The triangle produced AED is a right triangle with right angle at E (because AB is perpendicular to DC)
Angle D = 180- (90+Angle A)
= 180-(90+44)
= 46 Degrees
The sum of angles in a quadrilateral is 360
Angle B = 360-(Angle A+C+D)
= 360-(44+148+46)
= 122 Degrees
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