N quadrilateral ABCD, AB produced is perpendicular to DC produced. If A= 44 degree and C= 148 degree, Calculate angle D and angle B.?
pradeeptripathi:
Can you let me know, what kind of a figure would be made?
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Let AB produced meet DC produced at E
∠A = 44
∠C = 148
Δ AED is a right triangle with right angle at E thus;
∠D = 180 - (90 + ∠A)
= 180 - (90 + 44)
=46
∠D = 46 degrees
The sum of the angles in the quadrilateral is 360 thus
∠B = 360 - (∠A + ∠C + ∠D)
= 360 - (44 + 148 + 46)
∠B = 122 degrees
∠A = 44
∠C = 148
Δ AED is a right triangle with right angle at E thus;
∠D = 180 - (90 + ∠A)
= 180 - (90 + 44)
=46
∠D = 46 degrees
The sum of the angles in the quadrilateral is 360 thus
∠B = 360 - (∠A + ∠C + ∠D)
= 360 - (44 + 148 + 46)
∠B = 122 degrees
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