Physics, asked by shivammehta, 1 year ago

answer the 6th question

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Answered by MarilynEvans
13
 \mathsf{\huge{Answer}}

 \bold{Given\:that,}

Velocity = 20m/s

Distance = 6cm = 0.06m

Intial velocity = 0m/s

 \bold{To\:find,}

Deceleration of the bullet = ?

 \bold{By\:using\:3rd\:equation\:of\:motion}

 2(-a) s = v^2 - u^2

 \bold{By\:substituting\:the\:given\:values}

 2(-a) (0.06m) = (20m/s)^2 - (0m/s)^2

0.12(-a) = 400m/s - 0

0.12(-a) = 400m/s

-a =  \frac{400}{0.12}

-a = 3,333.3

a = - 3,333.3

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