Question

answer the 6th question ^_^

Answer 1

that is the answer of your question

Answer 2

Heya mate,Here is ur answer

Given : AD bisect angle A.

So, angle BAD= angle CAD

AD perpendicular BC

So, angle ADB= angle ADC(each 90°)

To prove : ∆ABC is an isosceles∆.

Proof:In ∆ ABD and∆ACD

AD=AD(common side)

angle BAD=angle CAD(Proved above)

angle ADB=Angle ADC (proved above)

So, ∆ADB congruent ∆ADC(ASA congruence rule)

Hence, AB=AC( By CPCT)

Hence, ∆ABC is an isosceles triangle.

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@Laughterqueen

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