Question

Answer the above one pls​

Answer 1

Answer:

x^2-y^2+y^2-z^2+z^2-x^2=0

Step-by-step explanation:

because we know that (a-b)(a+b)=a^2-b^2

please bro mark me as brainliest

Answer 2

Question

$\boxed{ \bf\: (x - y)(x + y) + (y - 2)(y + 2) + (2 - x)(2 + x)}$

Evaluate.

Answer

$\bf\: (x - y)(x + y) + (y - 2)(y + 2) + (2 - x)(2 + x)$

$\bf\mapsto(x {}^{2} - y {}^{2} )+ (y {}^{2} - 2 {}^{2} )+ (2 {}^{2} - x {}^{2} )$

$\bf\mapsto \: x {}^{2} - y {}^{2} + y {}^{2} - 2 {}^{2} + 2 {}^{2} - x {}^{2}$

$\bf\mapsto \: \cancel {x {}^{2} } - y {}^{2} + y {}^{2} - 2 {}^{2} + 2 {}^{2} \cancel{- x {}^{2} }$

$\bf\mapsto \: \cancel{- y {}^{2} }+ \cancel{y {}^{2} }- 2 {}^{2} + 2 {}^{2}$

$\bf\mapsto \: \cancel{- 2 {}^{2} }+ \cancel{2 {}^{2}}$

$\bf\mapsto \: 0$

$\small\rm \: formula \: used = \boxed{ \tt \: (a - b)(a + b) = a {}^{2} - b {}^{2} }$

Basic formulas

$\boxed{\tt { \color{navy} (a + b) {}^{2} = a {}^{2} + 2ab + b {}^{2} }}$

$\boxed{\tt { \color{purple} (a - b) {}^{2} = a {}^{2} - 2ab + b {}^{2} }}$

$\boxed{ \tt { \color{violet}(a - b)(a + b) = a {}^{2} - b {}^{2} }}$