Question

answer the above. please don't spam okay.​

Answer 1

Answer:

AOB=90

o

Join OC OC⊥AB

(Tangent at any pt of circle is far to radius)

∠ACO=∠BCO=90

o

In ΔAOP & ΔAOC

OP=OC

AP=AC (length of drawn from external point to circle are equal)

⇒ΔAOP≅ΔAOC

In ΔBOC & ΔBOQ

with same argument

ΔBOC≅ΔBOQ

∠BOC=∠BOQ (CPCT)

for line PQ

∠AOP+∠AOC+∠BOC+∠BOQ=180

2∠AOC=2∠BOC=180

⇒∠AOC+∠BOC=90

⇒∠AOB=90

hope it helps dear

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