Question

answer the above question​

Answer 1

Step-by-step explanation:

$\csc(90 + \alpha ) + x \cos( \alpha ) \cot(90 + \alpha ) = \sin(90 + \alpha ) \\ \\ \\ \sec( \alpha ) + x \cos( \alpha )( - \tan( \alpha ) )= \cos( \alpha ) \\ \\ \\ \sec( \alpha ) - x \cos( \alpha ) \frac{ \sin( \alpha ) }{ \cos( \alpha ) } = \cos( \alpha ) \\ \\ \\ \frac{1}{ \cos( \alpha ) } - x\sin( \alpha ) = \cos( \alpha ) \\ \\ \\ x \sin( \alpha ) = \frac{1}{ \cos( \alpha ) } - \cos( \alpha ) \\ \\ \\ x \sin( \alpha ) = \frac{1 - { \cos}^{2} \alpha }{ \cos( \alpha ) } \\ \\ \\ x \sin( \alpha ) = \frac{ { \sin }^{2} \alpha }{ \cos( \alpha ) } \\ \\ \\ x = \frac{ \sin( \alpha ) }{ \cos( \alpha ) } \\ \\ \\ x = \tan( \alpha )$

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