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Given that, 5 tanα = 4
==> tanα = 4/5
Now,
L.H.S.
= (5 sinα - 3 cosα)/(5 sinα + 2 cosα)
= (5 tanα - 3)/(5 tanα + 2),
dividing both the numerator and the denominator by cosα
= {5 (4/5) - 3}/{5 (4/5) + 2}
= {4 - 3}/{4 + 2}
= 1/6
= R.H.S.
Hence, proved.
==> tanα = 4/5
Now,
L.H.S.
= (5 sinα - 3 cosα)/(5 sinα + 2 cosα)
= (5 tanα - 3)/(5 tanα + 2),
dividing both the numerator and the denominator by cosα
= {5 (4/5) - 3}/{5 (4/5) + 2}
= {4 - 3}/{4 + 2}
= 1/6
= R.H.S.
Hence, proved.
Shobhit1903:
nice answer
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