Question

calculate the number of atoms of gold in 1 gram of gold

Answer 1

Answer:

Atomic weight of the Gold (Au) is = 196.97 (197g apprx.)

The Avogadro's number in one mole are = 6.022X10^23

That means 6.022X10^23  atoms weigh 196.97 g.

                   

Now

         1.0 g/ 196.97 g  = 0.0051 mol

So the number of atoms in one gram of gold are:

 0.0051 x 6.022X10^23   = 3.057318373 x 10^21

Answer 2

Here's your answer Buddy!

No. of atom present in 1g of gold (Au) =

Given Mass/Molar Mass ×Avagadro no.

= 1/198 × 6.022×10²³

=3.04×10²¹ atoms

Hope it's helpful! ヾ(❀╹◡╹)ﾉﾞ❀~