answer the above questions with proper explanation
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[I already solved 3 no. problem in your previous question. So, I am solving the 4th one only.]
The answer is given below :
Given,
a = 3 - √n, where n is a Natural number,
n = 1, 2, 3, ...
To find the least positive value of 'a', we need to put n = 2, so that 'a' becomes the least.
When n = 2,
a = 3 - √2
So, the least value of 'a' being 'p', p = 3 - √2
Now,
p = 3 - √2
= 2 - √2 + 1
= (√2)² - (2 × √2 × 1) + (1)²
= (√2 - 1)²
Since, p is positive,
√p = √2 - 1
and
1/√p = 1/(√2 - 1)
= (√2 + 1)/{(√2 - 1)(√2 + 1)},
by rationalising the denominator by multiplying both the numerator and the denominator by (√2 + 1)
= (√2 + 1), since (√2 - 1)(√2 + 1) = 2 - 1 = 1
Now,
√p + 1/√p
= √2 - 1 + √2 + 1
= 2√2
So, option (1) is correct.
Thank you for your question.
The answer is given below :
Given,
a = 3 - √n, where n is a Natural number,
n = 1, 2, 3, ...
To find the least positive value of 'a', we need to put n = 2, so that 'a' becomes the least.
When n = 2,
a = 3 - √2
So, the least value of 'a' being 'p', p = 3 - √2
Now,
p = 3 - √2
= 2 - √2 + 1
= (√2)² - (2 × √2 × 1) + (1)²
= (√2 - 1)²
Since, p is positive,
√p = √2 - 1
and
1/√p = 1/(√2 - 1)
= (√2 + 1)/{(√2 - 1)(√2 + 1)},
by rationalising the denominator by multiplying both the numerator and the denominator by (√2 + 1)
= (√2 + 1), since (√2 - 1)(√2 + 1) = 2 - 1 = 1
Now,
√p + 1/√p
= √2 - 1 + √2 + 1
= 2√2
So, option (1) is correct.
Thank you for your question.
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