Question

Answer the above with EXPLAINATION... THE BEST WILL GET BRAINLIEST
note= if your randomly wrote anything it will be reported!!!​

Answer 1

Answer:

Given is that the particle is being thrown at angle alpha to the horizontal, therefore the component of the velocity of the particle along the two dimension will be ux along the x axis and uy along the y axis.

Further the component derived from the velocity u has the value ux=u cos\alpha and uy similarly has uy=u sin\alpha.

If the angle changes to beta to the horizontal.

The new component of the new velocity V be Vx and Vy. As the X axis component does not change due to no change in position.

Vx = V cos\beta = u cos\alpha.

Therefore,

V cos\beta = u cos\alpha

V = u cos\alpha / cos\beta.

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