Question

Answer the below attached question on simple speed and time with explanation please?​

Answer 1

Answer:

Question:-

Two persons A and B start from the same location and walked around a square in opposite directions with constant speeds. The square has side 60 m. Speeds of A and B are 4m/s and 2m/s respectively. when will the meet first time ?

Solution:-

Find It:-

when will the meet first time ?

Given,

The square has side 60 m.

Speeds of A and B are 4m/s and 2m/s respectively.

Two persons A and B start from the same location and walked around a square in opposite directions with constant speeds.

$\bf \: according \: to \: the \: question$

Speeds of A are 4 x .

Speeds of B are 2 x .

Then ,

$\bf \: according \: to \: the \: question$

$\red{ \bf \: total \: distance = perimeter \: square \: }$

Putting the value in formula:-

$\bf \: 4x + 2x = 4 \times 60 \\ \: \bf \: add \: subtraction \: \\ \bf \: 6x = 240 \\ \\ \bf \: x = \frac{240}{6} \\ \\ \bf \red{ x = 40 \: sec }$

$\red{ \bf{ 40 \: sec \: }} \bf \: will \: the \: meet \: first \: time.$