Math, asked by JatinJalal, 1 month ago

answer the following class. 10th

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Answered by Leelagowtham
0

Step-by-step explanation:

i) a=1,b=6,c=-4

the roots=-b±√b²-4ac/2a

=-6±√36-4(1)(-4)/2×1

=-6±√36+16/2

=-6±√52/2

= -6±√4×13/2

=-6±2√13/2

=2(-3±√13)/2

=-3±√13

= -3+√13,-3-√13

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