Question

Answer the following

for the reaction
3 N2O+ 2NH3------> 4 N2 + 3H20 where ∆H=-879.6 kJ/mol

If ∆Hf[ NH3]=45.9 KJ/mol
∆Hf[H20] = -241.8 KJ/mol

Then ∆Hf[N20] will be


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Answer 1

Answer:

H20 c20 ..that is correct answer

Answer 2

Answer:

H20 c20 is the right answer...

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