Answer the following maths question please.
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Answered by
2
angle PCA = 110
angle PCO = 90
angle OCA = 110 - 90
= 20
angle OCA = angle OAC = 20(as triangle OCA is an isoceles triangle)
angle COA = 180- ( 20 + 20)
= 180 -40
= 140
angle CBA = angle COA/2
= 140/2
= 70
angle PCO = 90
angle OCA = 110 - 90
= 20
angle OCA = angle OAC = 20(as triangle OCA is an isoceles triangle)
angle COA = 180- ( 20 + 20)
= 180 -40
= 140
angle CBA = angle COA/2
= 140/2
= 70
Answered by
0
Hope this helps you out...
-------
angle PCA = 110
angle PCO = 90
angle OCA = 110 - 90= 20
angle OCA = angle OAC = 20
angle COA = 180- ( 20 + 20) = 180 - 40 = 140
angle CBA = angle COA/2= 140/2 = 70
-------
angle PCA = 110
angle PCO = 90
angle OCA = 110 - 90= 20
angle OCA = angle OAC = 20
angle COA = 180- ( 20 + 20) = 180 - 40 = 140
angle CBA = angle COA/2= 140/2 = 70
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