Question

answer the following question...​

Answer 1

Given:

BC = 30 m

Angle of elevation from C = 30°

Using applications of trigonometry:

tan30° = AB/BC

=> 1/√3 = AB/30

=> √3 AB = 30

=> AB = 30/√3

=> AB = √3*√3*10/√3

=> AB = 10√3 m

So, the height of the tower = 10√3 m

Answer 2

height = AB.

tan 30° = AB/BC

1/√3 = AB/ 30

AB = 30/√3

AB = 30*√3 / √3 * √3

AB = 30√3 / 3

AB = 10√3 cm ....