Question

answer the following questions

Answer 1

1. In ∆ ABD and ∆ ACD
AB= AC ( Given)
BD=DC (Given in the figure)
AD=AD ( Common)

Hence, ∆ADB≈ ∆ ADC

By SSS congruency rule.

Angle B= Angle C ( Corresponding part of congruent triangles).


2. In ∆ ABC and ∆ PQR
AC= PR( Both are of 4 cm)
BC= QR ( Both are of 3cm)
Angle ABC= Angle PRQ ( Both are of 60°)

So, ∆ ABC ≈ ∆ PQR
By SAS congruency rule.