Question

answer the following questions correct plzzzzzzzzz heple mi

Answer 1

tangential acceleration = 3 m/s^2

centripetal acceleration = v^2 / R = 20^2 / 100 = 400/100 = 4 m/s^2

Resultant acceleration = √(3^2 + 4^2) = √25 = 5 m/s^2

Acceleration = 5 m/s^2

Answer 2

Given Values:

Tangential speed = 20 m/s  

Radius of circular track = 100 m

Tangential acceleration = 3 m/s²

Now,

Centripetal acceleration = (Tangential speed)² / Radius  

= 20² / 100

= 400 / 100

= 4 m/s²

The resultant total acceleration is calculated by vector sum formula:

total acceleration² = (centripetal acceleration)² + (tangential acceleration)² + 2 * (centripetal acceleration) * (tangential acceleration) * cos Θ

But, here as the car in moving in a circular motion, the tangential acceleration is perpendicular to centripetal acceleration.

∴ cos Θ = cos 90 = 0

∴ total acceleration² = (centripetal acceleration)² + (tangential acceleration)² + 2 * (centripetal acceleration) * (tangential acceleration) * 0

= (centripetal acceleration)² + (tangential acceleration)² + 0

= (centripetal acceleration)² + (tangential acceleration)²

= 4² + 3²

= 16 + 9

= 25

∴ total acceleration = √25

= 5 m/s²

So, among the given options, the correct answer is the option number 3, i.e.; 5 m/s²

Hope you find this helpful!